MINISTRY OF EDUCATION AND VOCATION TRAINING
CHEMBA DISTRICT COUNCIL
FORM TWO MOCK ASSESSMENT
041 BASIC MATHEMATICS
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Instructions
1. This paper consists of ten (10) compulsory questions.
2. Show clearly all the working and answers in a space provided.
3. All writing must be in blue or black ink except drawing must be in pencil.
4. Mathematical tables, geometric instruments and graph papers may be used where necessary
5. All communication devices and calculators are not allowed in assessment room.
6. Write your assessment Number in top write corner of every page.
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FOR ASSESSOR’S USE ONLY |
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1 (a) Find the sum of all prime numbers between 80 and 100
(b) Round off:
(i) 9.67 to ones,
(ii) 0.205 to one decimal place,
(iii) 0.197 to two decimal places,
Hence, estimate the value of
2. (a) Evaluate 0.4 + 25% (0.22 0.2) + 0.45)
(b) If the new price of selling shoe is 40000Tsh. Find the percentage increase of price if the old price was 30000Tsh.
3. (a) If the bus starts the journey from Babati at 0600 and takes eight hours and a half to reach at Chemba bus terminal. Write the time taken to reach in 24 hours clock.
(b) If 50000Tsh of money was invested at a bank which provide the rate of 5%. Find the amount at a bank after 4 years.
4 (a) Find the value of an angle marked in letter f,g and k in the figure below.
b) Find the perimeter of square ,if its area is 36cm2
5 (a) The sum of two numbers is 127. If thedifference between the number is 7, Find the numbers
(b) Solve the equation by using quadratic formula.
6 a) If the line passes through the point (3,4) and (2,6). Find
i) The slope of the line.
ii) The equation of line in form of Y = MX+C
b) The vertices of the triangle are A(2,2) , B (3,4) and C (4,3). If the triangle is reflected under x-axis ,Write down the coordinate of the image of points A, B and C
7. (a)Find the value of p given that ( )2p +1 = ( )3p.
(b) (i) Find the value of 0.0000125 in standard notation.
(ii) Simplify the expression (3 + ) (4 )
8 (a) solve for the x in the inequality
3X – 4>, X+16
(b) Factorize the expression a2-b2
Hence find the exact valueof 6722-3282
9 the right angled triangle in the figure below has sides of length 7 , 24 cm and 150cm
S
(a)Calculate the value of .
(b)Calculate the area of the triangle
10 (a) There are 48 men at the meeting of whom 24 are teachers, 36 are parents and 16 are both teachers and parents . By using venndiagram , find the number of men who are neither teacher nor parents.
b) The marks of 100 student were recorded as follow,
|
Marks |
41 - 50 |
51 -60 |
61 - 70 |
71 - 80 |
81 -90 |
91 - 100 |
|
Number of students |
10 |
22 |
34 |
25 |
7 |
2 |
i) Which mark were scored by many student ………………………………….
ii) Which marks was the lowest mark ………………………………………………….
iii) If 50% was the pass mark of the test if above 50%, How many student passed examination
MINISTRY OF EDUCATION AND VOCATION TRAINING
CHEMBA DISTRICT COUNCIL
FORM TWO MOCK ASSESSMENT
041 BASIC MATHEMATICS
MARKING SCHEME
01. a) prime numbers between 80 and 100
Sum: 83 +89+91+97 =360 (5 marks)
b) i) 10 (1 mark)
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iii) 0.2(1 mark)
=
= 10(1 mark)
02 a) 0.4 + (25% 
(0.22
0.45)
o.4 +(
1.1) + 1/4
0.45)
0.4 + (0.25 
+
0.25 0.45) (05 marks)
0.90 – 1.1-0.45
-0.65
b) new price (NP) = 40000
0ld price (OP) = 30000
Difference cost (DP) = NP-OP
=
40000 
DP = 10000
Percentage cost increase = 
100%
= 
100%
= 
100%
Percentage cost increase = 33.33% (05 marks)
03 a) The bus Started Babati 0600
Time taken =8 :30 hours (02 marks)
Time taken to reaches Msamvu = 1430hrs (02 marks)
b) Principal (P) = 50000/=
Rate (R) =5%
Time taken (T) = 4years
Amount corrected (A)= ?
From; I
= 
(01mark)
= 
(01mark)
Interest (I) = 10000/=
Amount (A) = Principal + Interest
= 50000/= + 10000/= (01mark)
= 60000/=
Amount corrected after 4 years =60000/= (01mark)
04.
56
+ 50 + g =180
106 +g =180
g =180
106
g= 74
30 + g + h = 180
But; g = 74
30 + 74 + h = 180
104 + h = 180
h = 180 104
h = 76
f + k +30 = 180
but f =h
f = 76
76 + k +30 = 180 (06 marks)
K + 106 = 180
K
= 180 106
K = 74
|
f |
k |
g |
|
76 |
74 |
74 |
b) Area of square = 36cm2
Area = L
L (01mark)
36cm2 = L2
6cm = L (01mark)
Length of square = 6cm
Perimeter = 2(L + W)
=2 (6cm +6cm) (01mark)
= 212cm
Perimeter of square = 24 cm (01mark)
5a) Let ; first number be x
Second number be y
…………(i)
……………….(ii)
By elimination method
+
2
=127 + 7
2 =134
= 67
Y 
=127 
2y = 120
Y = 60
X,y = 67 ,60
b) 4
a = 4 , b = -32 and c =12
consider general guadratic formulae
x =
6 (a) points (3,4) and (2,6)
(i) Slope = 
Slope = 
Slope = 
Slope = -1
(ii) Equation
Slope = 
But slope =-1
-1 =
-1(2
= 6 
-2 + x = 6
Y = x
+ 6 + 2
Y =
x
+ 8
b) Reflection under x- axis
|
point |
2,2 |
3,4 |
4,3 |
|
reflection |
2,-2 |
3,-4 |
4,-3 |
7 (a) 
)2p
+ 1 =( 
)3p
)2p
+ 1 = ( 
)6p
)2p
+ 1 = ( 
)-6p
2p + 1 =-6p
2p + 6p = -1
8p = -1
P = 
( b)
0.0000125 8000 =(1.25 105) 
8
3)
=
1.25 8
1053
= 10 108
= 1
1 108
=
1 9
ii) (3 + 
)(4 2) = (3 4 6 + 4
2
)
=
(12 222)
=
8 - 2
(3 + 
)(4
2) = 8 – 2
8. (a) Required to show that
Now consider tri
Angle APQ and ABC
Then, 
(corresponding sides)
(Corresponding sides)
(Corresponding sides)
Hence, triangle APQ is similar to triangle ABC by (sss)
(b) Given a rectangular ABCD and WXYZ as shown below,
Then, ratios of the corresponding sides are given as
Hence value of 
9. (a) from Pythagoras theorem
a2 
b2
= c2
(7x)2 + (24x)2 = 1502
49x2 + 576x2 = 22500
625x2 = 22500
X2 = 
X2 = 36
X = 6
( b) given
5
= 3
Consider the triangle
from Pythagoras theorem
a2 b2
= c2
32 + b2 = 52
9 + b2 = 25
b2 = 25 – 9
b2 = 16
b = 4
= 
2
+ 3 
= 2 
10. (a) Consider the figure below,
From the figure above where P is parent, T is teachers and U is union, then
There for, 4 men are neither teacher nor parents
(b) From the given figure,
(i) Marks scored by many students is at the highest frequency 34
Hence, 61-70 marks are scored by many students.
(ii)Lowest marks is at frequency of 10, hence the lowest marks is 41-50
(iii) If 
was pass mark, then students who pass
examination is 
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