Integration :Is the reverse process of differentiation, i.e. the process of finding the expression for y in terms of x when given the gradient function.
The symbol for integration is
This is the general power of integration it works for all values of n except for n = -1
Example
1.
2. Integrate the following with respect to x
(i)3x2
Solution
Integration of constant
Integration by change of variables
If x is replaced by a linear function of x, say of the form ax + b, integration by change of variables will be applied
E.g
Example
Note: 2x is the derivative of x2 + 1 in this case substitution is useful
i.e. let u = x2 + 1
This converts into the form
Standard integrals
·
EXERCISE
Find the integral of the following functions
gration by partial fraction
Integration by partial fraction is applied only for proper fraction
E.g.
Note that:
Improper fraction
If the degree of numerator is equal or greater than of denominator, adjustment must be made
Example
1. Find
Solution
If the denominator doesn’t factorize, splitting the numerator will work
→ Numerator = A (derivative of denominator) + B
Example
Solution
Important
It can be shown that
EXERCISE
Integrated of the form
Note that:
1. If the denominator has two real roots use partial fraction
2. If the denominator has one repeated root use change of variable or recognition
3. If the denominator has no real roots, use completing the square
Integration of Trigonometric Expression
Integration of Even power of
Note that
For integrand containing and , or even powers of these, the change of variable can be used.
APPLICATION OF INTEGRATION
To determine the area under the curve
= f (b) – f (a)
Examples
1. Find the area under the curve f(x) =x2+1 from x=0 to x=2
2. Find the area under the curve f(x) = from x=1 to x=2
3. Find the area bounded by the function f(x) =x 2-3, x=0, x=5 and the x- axis
Solution
- f(x) = + 1
y intercept=1
EXERCISE
1. Find the area between y = 7-x2 and the x- axis from x= -1 to x=2
2. Find the area between the graph of y=x2 x – 2 and the x- axis from x= -2 to x=3
Solution
1. y =7-x2
Where y- intercept =7
= 6.67 + 11.3
=17.97sq units
Volume of the Solids of Revolution
The volume,V of the solid of revolution is obtained by revolving the
shaded portion under the curve, y= f(x) from x= a to x =b about the x
-axis is given by
Example 1
Find the volume of revolution by the curve y=x2 from x=0 to x=2 given that the rotation is done about the the x- axis
Exercise
1. Find the volume obtained when each of the regions is rotated about the x – axis.
a) Under y= x3, from x =0 to x=1
b) Under y2= 4-x, from x=0 to x=2
c)Under y= x2, from x=1 to x=2
d)Under y= √x, from x=1 to x=4
2. Find the volume obtained when each of the region is rotated about the y-axis.
a) Under y= x2, and the y-axis from x=0 to x=2
b) Under y= x3, and the y-axis from y=1 to y=8
c) Under y= √x, and the y-axis from y=1 to y=2
LENGTH OF A CURVE
Consider the curve
Example
Find the length of the part of the curves given between the limits:
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